In a simple series circuit with a 6 V supply and total resistance 5 Ω, what is the current?

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Multiple Choice

In a simple series circuit with a 6 V supply and total resistance 5 Ω, what is the current?

Explanation:
Current in a simple circuit is found using Ohm’s law: I = V / R. With a 6 V supply and a total resistance of 5 Ω, the current is 6 divided by 5, which equals 1.2 A. In a series circuit, the same current flows through every component, so this 1.2 A is what flows around the loop. If you check the other options, they would require different total resistances: 0.8 A would need 7.5 Ω, 2.0 A would need 3 Ω, and 6.0 A would need 1 Ω. Since the total resistance here is fixed at 5 Ω, the only consistent current is 1.2 A.

Current in a simple circuit is found using Ohm’s law: I = V / R. With a 6 V supply and a total resistance of 5 Ω, the current is 6 divided by 5, which equals 1.2 A. In a series circuit, the same current flows through every component, so this 1.2 A is what flows around the loop.

If you check the other options, they would require different total resistances: 0.8 A would need 7.5 Ω, 2.0 A would need 3 Ω, and 6.0 A would need 1 Ω. Since the total resistance here is fixed at 5 Ω, the only consistent current is 1.2 A.

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